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二维数组按列求和jAvA
2020-10-11

二维数组的话,必须循环行和列,之后求总和即可:public class Test { public static void main(String args[]) throws ParseException { int [][]a = {{1,2,4,5},{6,7,8,9},{10,11,12,13},{14,15,16,17}}; int sum =0; //设置sum为0,方便计算 for(int i = 0; i < a.

public class CountSum { public static void main(String[] args) { double[] 牛奶={357,67,98,345.5,66.5,145.5}; double[] 苹果={135,674,98,345.5,200,245.5}; double[] 肥皂={245,178,98,346,66.5,289}; System.out.println("牛奶: "+getSum(牛奶)

public int sum(int[][] a2){ int sum = 0; for(int i=0;i for(int j = 0;j sum+=a[i][j]; } } return sum; }

public class TestSort { public static void main(String[] args) { String[][] s = new String[][] { { "01", " 张三", " 男", "28" }, { "02 ", "李强", " 男", "23" }, { "03 ", "王五", " 男", "26" }, { "04 ", "李艳 ", "

sum=0;for(int i=0;i<list.size();i++) sum+=list.get(i)*k;我觉得教出写出这种代码的人的人该处死刑 = =这都什么玩意啊

不用计算,java中的数组自带length属性,例如:假设有个二维数组a[][] a.length就是行数,a[0].length就是列数

public class ArraySum{ public static void main(String[] args) { int[] a1 = {1, 2, 3, 4}; int[] a2 = {5, 6, 7, 8}; int sum = 0; for (int i=0; i<a1.length; i++) { sum = sum + a1[i]; } for (int i=0; i<a2.length; i++) { sum = sum + a2[i]; } System.out.println("2数组总和是: " + sum); }}

应该没有这种直接按列读取数组数据的方法吧(也可能没找到),即使有,那获取的方法也肯定是通过两重循环package servlet;import java.util.ArrayList;import java.util.List;public class GetArrayByColumn { /** * @param args */ public List<String>

假设a是待处理的二维数组public String[][] (String[][] a){ int b1 = 0,b2 = 0; int no1 = 0; int no2 = 0; for(int h = 0; h0.2){ b1++; } } } if(no1/no2 追问: 这样弄结果为什么还是java.lang.ArrayIndexOutOfBoundsException: 1呢 是不是我定义二维数组定

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